Posted by **Anonymous** on Wednesday, May 12, 2010 at 9:50pm.

A soccer player kicks a rock horizontally off the a 40 m high cliff into the pool of water. if the player hears the sound of the splash 3 sec., what is the initial speed given to the rock? Assume the speed of the sound in air to be 343 m/s.

- Physics -
**Damon**, Wednesday, May 12, 2010 at 10:02pm
Time for rock to fall 40 meters?

d = (1/2) a t^2

40 = (1/2)(9.8) t^2

t^2 = 8.16

t = 2.86 seconds

so the sound traveled for 3-2.86 = .143 seconds

so the rock hit 343*.143 = 49 meters away

that is hypotenuse of angle

with leg 40 and other leg is horizontal distance d from bottom of cliff to splash

d = sqrt (49^2 -40^2)

d = 28.3 meters

so rock hit 28.3 meters from cliff base in its 2.86 meters in the air

speed = distance/time = 28.3/2.86 = 9.9 m/s

- Physics -
**Wai**, Tuesday, February 2, 2016 at 1:55am
sample answer step by step

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