Hi,

I have had to factorise the equation
x^2 + x - 30 = 0, which I think I have worked the answer out as x =-6, x =5?

I now need to explain how I can use this answer to solve the equation
4x^2 +4x -120 =0

Any advice?

You would take your answers and plug them in to the equation.

4(-6^2)+4(-6)-120=0
and
4(5^2)+4(5)-120=0

then work out the problems and if you are correct 0=0

Hope this helped

To use the solutions of the equation x^2 + x - 30 = 0 (x = -6 and x = 5) to solve the equation 4x^2 + 4x - 120 = 0, you can follow these steps:

Step 1: Rewrite the equation using the solutions for x from the first equation:
4(x^2 + x - 30) = 0

Step 2: Simplify the equation:
4x^2 + 4x - 120 = 0

Step 3: Divide both sides of the equation by 4 to isolate the quadratic term:
x^2 + x - 30 = 0

Step 4: Notice that this equation is exactly the same as the first equation, x^2 + x - 30 = 0, which you have already solved. Therefore, you can use the same solutions for x: x = -6 and x = 5.

So, the solutions for the equation 4x^2 + 4x - 120 = 0 are also x = -6 and x = 5.