Posted by **Courtney** on Wednesday, May 12, 2010 at 12:12pm.

find, to the nearest degree, the solution set of 4 cos^2x-1=0 in the intervak between )degrees and 360degrees.

- trig -
**Reiny**, Wednesday, May 12, 2010 at 1:10pm
4 cos^2x-1=0

cos^2 x = 1/4

cosx = ± 1/2

In I x = 60

in II , x = 180-60 = 120

in III, x = 180+60 = 240

in IV , x = 360-60 = 300

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