Posted by Courtney on Wednesday, May 12, 2010 at 12:12pm.
find, to the nearest degree, the solution set of 4 cos^2x1=0 in the intervak between )degrees and 360degrees.

trig  Reiny, Wednesday, May 12, 2010 at 1:10pm
4 cos^2x1=0
cos^2 x = 1/4
cosx = ± 1/2
In I x = 60
in II , x = 18060 = 120
in III, x = 180+60 = 240
in IV , x = 36060 = 300
Answer This Question
Related Questions
 advanced functions(trig)  solve for x, to the nearest degree, in the interval ...
 trig  Find, to the nearest degree, the solution set of 3sin^2x = 5 cosx+1 over ...
 HELPPPPPPP (TRIG)  find, to the nearest minute, the solution set of 1 sin x = ...
 trig  find, to the nearest minute, the solution set of 1 sin x = 3 cos^2 x ...
 trig  find, to the nearest minute, the solution set of 4 cos x + 5 = 6 sec x ...
 trig  ind, to the nearest minute, the solution set of 4 cos x + 5 = 6 sec x ...
 trig/math  If A is between 270degrees and 360degrees, and cos A=12/13, find the...
 trig  To the nearest degree, all of the following angles are solutions of the ...
 trig  find to the nearesr degree, all values of x between 0 degrees and 360 ...
 trig  Give the measure of the acute angle with each given value to the nearest ...
More Related Questions