Posted by **Courtney** on Wednesday, May 12, 2010 at 12:11pm.

Given 2secant^2 (theta) + 1 = 5 secant (theta), solve for (theta), to the nearest degree, in the interval 0 degrees is greater than or equal to (theta) which is less than 360 degrees

- Trig -
**Reiny**, Wednesday, May 12, 2010 at 1:20pm
let sec(theta) = x

so we have

2secant^2 (theta) + 1 = 5 secant (theta) becomes

2x^2 + 1 = 5x

2x^2 - 5x + 1 = 0

x = (5 ± √17)/4

= 2.2808 or .21922

so sec(theta) = 2.2808

cos(theta) = 1/2.2808 = .43844 , so theta is in I or IV

theta = 63.995 or 64º or theta = 296º

or

sec(theta) = .21922

cos(theta) = 1/.21922 = 4.56 ---> not possible

theta = 64º or 296º

## Answer This Question

## Related Questions

- trig - what are the values of theta in the interval 0 degrees is lessthan or ...
- trig - find two values of theta, zero degrees is than or equal to theta which is...
- Trig - Solve the following interval 0<_ (less than or equal to)0(Theta)<...
- trig - If cosecant of theta equals 3 and cosine of theta is less than zero, find...
- trig - I don't understand how to do this type of question? If 9cos^2 theta +...
- trig - For the given equation, solve for all values of (theta) to the nearest ...
- trig - i nead to find to the nearest degree all values of theta in the interval ...
- algebra/trigonometry - What are the values of theta in the interval 0degrees ...
- trig - If sin theta is equal to 5/13 and theta is an angle in quadrant II find ...
- trig - If tan theta = sin theta, and theta is greater than or equal to 0 and ...

More Related Questions