Posted by **Jake** on Wednesday, May 12, 2010 at 1:08am.

In this problem, you will describe in detail how we arrive at the accepted definition of the function y= Arccsc(x)

a) Sketch the cosecant function over the interval (-2pi, 2pi)

i can do that

b) This function is not one to one - please explain in detail the meaning of this

???

c) how would you restrict the domain of the cosecant function so that it becomes a one to one function?

???

d) By restricting the function as described in part c) what is the domain and range of this resulting function. Use interval notation.

e) From part d) what is the domain and range of the inverse function

y = arccsc(x).

## Answer This Question

## Related Questions

- trigonometry - Graph the function f(x)=-1/2sin2x+1 on the interval [-2pi, 2pi]
- calc - i did this problem and it isn't working out, so i think i'm either making...
- ordinary differential equation - a periodic function f(t) is defined by f(t) = t...
- Pre calculus/ Advanced Functions - Samuel is investigating the rate of change of...
- trig - find the period and amplitude of each sine function.then sketch each ...
- Trig help - 1. What is the period of the function? y = 4 cos pi x A. 1 B. 2 C. ...
- calculus - Given the function f (x) = 3cos x for the interval 0 < x < 2pi...
- Pre-Calculus - The period T (in seconds) of a simple pendulum is a function of ...
- Trigonometry - function y=4-2sin(2t+pi/2), where t is measured in radians. ...
- Trigonometry - A sine function has an amplitude of 4/7, period of 2pi, ...

More Related Questions