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November 28, 2014

November 28, 2014

Posted by **carol** on Wednesday, May 12, 2010 at 12:27am.

The standard deviation of the ages in Room A is zero; the standard deviation of the ages in Room B is 12.25. So, when we say that for Room B the mean is 25 and the standard deviation is 12.25, we get a better picture of the age distribution in the room. Standard deviation is a measure of the "spread" in the data.

Also, how did I get 12.25? How was it calculated?

- statistic -
**Mahendra**, Wednesday, May 12, 2010 at 1:28amStandard Deviation = SQRT [ {sqr(10-25) + sqr (25-25) + sqr (40-25)}/3 ]

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