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April 20, 2014

April 20, 2014

Posted by **Heather** on Tuesday, May 11, 2010 at 4:13pm.

2x+20y= -144

12x+5y= 56

- Math -
**anonymous**, Tuesday, May 11, 2010 at 6:13pmIn one equation, solve for one of the variables in terms of the other. For instance,

2x+20y=-144

2x=-144-20y

x=-72-10y

Then plug this variable into the other equation in order to yield a constant for y.

12(-72-10y)+5y=56

-864-120y+5y=56

-864-115y=56

-115y=920

y=-8.

But you're still not done. You have to plug this back into the equation in which you solved for x so you can get a constant value for x as well.

x=-72-10(-8)=-72+80=8

So x=8 and y=-8.

Please try a similiar problem like this on your own so you are able to fully understand how to go about solving systems of equations. This site is here to help you, not do your homework for you. You won't learn anything if you just copied what I just typed up. Learning comes best when cemented independently.

Good luck, and peace out.

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