A steel container of oxygen has a volume of 20.0 L at 22 C @35 atm. What is the volume @ STP? How many mol of oxygen are in the container?
i got the answer, 2.37L..and 28.90 mol.. but that doesnt seem right to me, wouldnt it be the other way around?
P1V1/T1= 2.37 L
n=PV/RT= 28.90 mol
or should they be switched?
I worked the problem and obtained 28.916 mol which rounds to 28.9 to three s.f. but 2.37 L isn't close.
P1V1/T1 = 2.37. That is right; however, that isn't V2.
You must equate 2.37 on the left to P2V2/T2 and plug in standard conditions. As Bob Pursley wrote,
P1V1/T1 = P2V2/T2 and you have solved only half the equation.
.0820 L?
no.
Post your work and I'll find what you are doing wrong.
2.37= 1atm*22.4L/273K
Pray tell, what is the unknown. You have no unknown. In addition, what you have written is not an equality. 22.4/273 certainly isn't = 2.37.
What is the problem asking for? I thought it wanted you to calculate the new volume at the new conditions? It asks, "What is the volume at STP?"
Yes. i don't know why im having such a problem with this.
35atm820.0L/295K= 2.37
and the stp are, 273K, 1 atm, and 22.4 L
No. STP conditions are 273 K and 1 atm p. Your problem, I think, is that you have somehow convinced yourself that the volume is 22.4 L since that is the volume of a mole of gas at STP. But you don't have a mole of gas. You have already figured moles at 28.9 or so and you have much more than 1 mole of gas. You must have much more than 22.4 if you have almost 30 moles of gas.
p1 = 35 atm
V1 = 20.0 L
T1 = 273 + 22 = 295
P2 = 1 atm
V2 = unknown, solve for this.
T2 = 273
(35*20.0/295) = (1*V2/273)
Solve for V2.
(35*20.0/295) = (1*V2/273)
To find the volume of the steel container at STP (Standard Temperature and Pressure), we need to convert the given conditions to STP conditions.
STP conditions are defined as 0 degrees Celsius (273.15 K) and 1 atmosphere pressure (1 atm).
Given:
- Volume (V₁) of the container = 20.0 L
- Temperature (T₁) = 22 °C = 22 + 273.15 K = 295.15 K
- Pressure (P₁) = 35 atm
Let's use the combined gas law to solve for the volume at STP.
The combined gas law is given by:
(P₁ * V₁) / T₁ = (P₂ * V₂) / T₂
Where:
- P₂ = Pressure at STP (1 atm)
- V₂ = Volume at STP (to be determined)
- T₂ = Temperature at STP (273.15 K)
Rearranging the equation to solve for V₂:
V₂ = (P₁ * V₁ * T₂) / (P₂ * T₁)
Substituting the given values:
V₂ = (35 atm * 20.0 L * 273.15 K) / (1 atm * 295.15 K)
Calculating this expression will give us the required volume at STP.
Next, let's calculate the number of moles of oxygen present in the container.
To calculate the number of moles, we can use the ideal gas law, which states:
PV = nRT
Where:
- P = Pressure
- V = Volume
- n = Number of moles
- R = Gas constant (8.314 J/mol·K)
- T = Temperature
Rearranging the equation to solve for n:
n = (PV) / (RT)
Substituting the given values:
n = (35 atm * 20.0 L) / (0.0821 atm·L/mol·K * 295.15 K)
Calculating this expression will give us the number of moles of oxygen in the container.