Formula given: H=7+70t-16tsquared. Ball kicked straight up from a height of 7 feet. Ball travels 70 feet per second. How high is the ball after 3 seconds (t)?
Plug in 3.0 for t in your H vs. t equation. You should not have a problem doing that.
The equation you are given already takes into account the speed and direction that the ball was kicked, and the acceleration of gravity. All you have to do is substitute 3 for t and "turn the crank".
To find the height of the ball after 3 seconds (t), we can substitute the value of t into the given formula and solve for H.
The formula given is: H = 7 + 70t - 16t^2
Substituting t = 3 into the formula, we have:
H = 7 + 70(3) - 16(3^2)
= 7 + 210 - 16(9)
= 7 + 210 - 144
= 217 - 144
= 73
Therefore, the ball is at a height of 73 feet after 3 seconds.