Posted by Nathan on .
Assume the body temperatures of healthy adults are normally distributed with a mean of 98.20 °F and a standard deviation of 0.62 °F (based on data from the University of Maryland researchers).
a. (0.1 point) If you have a body temperature of 99.00 °F, what is your percentile score?
b. (0.1 point) Convert 99.00 °F to a standard score (or a z-score).
c. 1. (0.1 point) Is a body temperature of 99.00 °F unusual?
2. (0.1 point) Why or why not?
d. (0.1 point) Fifty adults are randomly selected. What is the likelihood that the mean
of their body temperatures is 97.98 °F or lower?
e. (0.1 point) A person’s body temperature is found to be 101.00 °F. Is the result unusual?
(0.1 point) Why or Why Not and What should you conclude?
f. (0.1 point) What body temperature is the 95th percentile? :
g. (0.1 point) What body temperature is the 5th percentile?
Z = (x - mean)/SD
Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion related to the Z score.
You can also reverse the process to get the Z score for a percentile and plug that in the above formula to get the temperature.
Make your own conclusions.