Homework Help: statistics

Posted by Nathan on Monday, May 10, 2010 at 11:57pm.

Assume the body temperatures of healthy adults are normally distributed with a mean of 98.20 °F and a standard deviation of 0.62 °F (based on data from the University of Maryland researchers).

a. (0.1 point) If you have a body temperature of 99.00 °F, what is your percentile score?

b. (0.1 point) Convert 99.00 °F to a standard score (or a z-score).

c. 1. (0.1 point) Is a body temperature of 99.00 °F unusual?

2. (0.1 point) Why or why not?

d. (0.1 point) Fifty adults are randomly selected. What is the likelihood that the mean

of their body temperatures is 97.98 °F or lower?

e. (0.1 point) A person’s body temperature is found to be 101.00 °F. Is the result unusual?

(0.1 point) Why or Why Not and What should you conclude?

f. (0.1 point) What body temperature is the 95th percentile? :

g. (0.1 point) What body temperature is the 5th percentile?

statistics - PsyDAG, Tuesday, May 11, 2010 at 3:12pm
Z = (x - mean)/SD

Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion related to the Z score.

You can also reverse the process to get the Z score for a percentile and plug that in the above formula to get the temperature.

Make your own conclusions.

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