Calculate how far and apart two indentical charges of 1.0 C must be in order for the Coulomb force between them be less than 500 N
F=kqq/d^2
solve for d
Thanks for the given equation.
To calculate the distance at which the Coulomb force between two identical charges is less than 500 N, we can use the formula for Coulomb's law:
F = k(q1 * q2) / r^2
Where:
F is the Coulomb force between the charges,
k is Coulomb's constant (8.99 x 10^9 N*m^2/C^2),
q1 and q2 are the magnitudes of the charges, and
r is the distance between the charges.
In this case, since the charges are identical, we can replace q1 and q2 with just q.
Given that F should be less than 500 N, and q = 1.0 C, we can rearrange the formula to solve for r:
r = sqrt(k * q^2 / F)
Substituting the values, we get:
r = sqrt((8.99 x 10^9 N*m^2/C^2) * (1.0 C)^2 / 500 N)
Simplifying the expression:
r = sqrt(8.99 x 10^9 N*m^2/C) / sqrt(500 N)
Using a calculator, we find:
r ≈ 9.5 meters
Therefore, the charges must be at least 9.5 meters apart for the Coulomb force between them to be less than 500 N.