calculate the force between two identical charges of 1.0 x 10 exp -9 C separated by 1.0 Cm

for same question above if the charge is increased by a factor of 10 what number am I increasing? and am I increasing it by adding or multiplying?

When you are talking factors. you increase by multiplying.

A factor of 10 increase in the charge increases the force by a FACTOR of 100, since the charge gets squared when the two charges are equal.

To calculate the force between two charges, you can use Coulomb's Law. Coulomb's Law states that the force between two charges is directly proportional to the product of their magnitudes and inversely proportional to the square of the distance between them.

The formula for Coulomb's Law is:

F = (k * q1 * q2) / r^2

Where:
F is the force between the charges,
k is the electrostatic constant (9 x 10^9 N m^2/C^2),
q1 and q2 are the magnitudes of the charges, and
r is the distance between the charges.

In your case, the magnitude of each charge is 1.0 x 10^(-9) C, and the distance between them is 1.0 cm (which is equivalent to 0.01 m).

Let's plug these values into the formula:

F = (9 x 10^9 N m^2/C^2) * (1.0 x 10^(-9) C) * (1.0 x 10^(-9) C) / (0.01 m)^2

Simplifying the calculation:

F = (9 x 10^9) * (1.0 x 10^(-9))^2 / (0.01)^2

F = 9 * 1.0 x 10^(-9)^2 / 0.01^2

F = 9 * 1.0 x 10^(-18) / 0.0001

F = 9 x 10^(-18) / 0.0001

F = 9 x 10^(-14) N

Therefore, the force between the two identical charges is 9 x 10^(-14) Newtons.

Look up Coulomb's Law in your textbook or course notes.

F = k Q1*Q2/r^2

Depending upon which constant k you use, you may need to convert the r = 1 cm separation to 0.01 m.