Physics
posted by Adrionna on .
An archer applies an average force of 200 N to draw the bow string back 1.3 m.
a)How much work did the archer do on the string?
b)How much mechanical potential energy is stored in the stretched bow?
c)How much kinetic energy does the arrow have before it is released?
d)How much potential energy will the arrow have after it leaves the bowstring?
e)If a 0.3 kg arrow is shot from this bow, then how fast will it be moving just after it leaves the bowstring?

I will be happy to critique your work.

OK SO PLEASE EXPLAIN TO ME HOW TO DO THIS

a. work=avgforce*distance
b.PE=above work. KEwhenreleased=InitialPE
d. zero, no PE, it has KE.
e. Initial energy=1/2 m v^2
solve for v. 
Idk wat it is