Posted by Adrionna on Monday, May 10, 2010 at 2:59pm.
I will be happy to critique your work.
OK SO PLEASE EXPLAIN TO ME HOW TO DO THIS
a. work=avgforce*distance
b.PE=above work. KEwhenreleased=InitialPE
d. zero, no PE, it has KE.
e. Initial energy=1/2 m v^2
solve for v.
Related Questions
physics - An archer puts a 0.26-kg arrow to the bow-string. An average force of ...
Physics - An archer puts a 0.26-kg arrow to the bow-string. An average force of ...
physics - An archer puts a 0.26-kg arrow to the bow-string. An average force of ...
physics - An archer pulls her bow string back 0.400 m by exerting a force that ...
physics - An archer locks a 0.20kg arrow on a bowstring. Then the archer exerts ...
physics - When archer pulls an arrow back in his bow.He is storing potential ...
Physics - Pulling the string on a bow back with a force of 28.7 lb, an archer ...
Physics - Pulling the string on a bow back with a force of 28.7lbs, an archer ...
Physics - An archer puts a 0.28 kg arrow to the bow string. An average force of ...
physics - An arrow with a mass of 0.12 kg is pulled back in a bow. After being ...
For Further Reading