How many excess electrons does an object with a total charge of -1.0 x 10exp-9C have on it? This is approximately the amount of charge involved in commonly encountered static electricity.
Divide the charge by the charge on one electron.
So if one electron is 1.6 x 10 exp -19 C it would be -1.0 x 10exp-9C divided by 1.6 x 10 exp -19 C correct?
To calculate the number of excess electrons on an object with a given total charge, you can use the elementary charge, which is approximately 1.6 x 10^-19 C.
In this case, the total charge of the object is -1.0 x 10^-9 C.
To find the number of excess electrons, divide the total charge by the elementary charge:
Number of excess electrons = total charge / elementary charge
= (-1.0 x 10^-9 C) / (1.6 x 10^-19 C)
Calculating this, you get:
Number of excess electrons ≈ -6.25 x 10^9 electrons
Therefore, an object with a total charge of -1.0 x 10^-9 C has approximately -6.25 x 10^9 excess electrons on it.
To determine the number of excess electrons on an object with a given charge, we need to use the elementary charge, which is the charge of a single electron. The elementary charge is approximately equal to -1.6 x 10^-19 Coulombs (C).
Given that the total charge of the object is -1.0 x 10^-9 C, we can determine the number of excess electrons by dividing the total charge by the elementary charge:
-1.0 x 10^-9 C / (-1.6 x 10^-19 C/electron)
Simplifying this division, we get:
(1.0 x 10^-9 C) / (1.6 x 10^-19 C/electron)
Now, dividing the numerator and denominator by 1.0 x 10^-19, we have:
(1.0 x 10^-9 C / 1.0 x 10^-19 C) / (1.6 / 1.0)
Further simplifying, we get:
1.0 x 10^10 / 1.6
Finally, dividing 1.0 x 10^10 by 1.6, we find:
6.25 x 10^9
Therefore, an object with a total charge of -1.0 x 10^-9 Coulombs has approximately 6.25 x 10^9 excess electrons on it.