Homework Help: Unit Cells

Posted by CHeM on Sunday, May 9, 2010 at 11:00pm.

Copper has a unit cell volume of (47.453 A^3) and a face centered unit cell. How would I go about finding the volume of atoms within the unit cell? Would you use Avogadro's # somehow?

Unit Cells - DrBob222, Sunday, May 9, 2010 at 11:27pm
I don't get the 47.453 A^3 for volume. That seems far too large (of course that depends upon what A stands for).
Whatever the volume, then
V^1/3 = length of an edge of the unit cell = a. Then 4r = a(2^{1/2).

When you have found r (radius of the atom), then volume of the atom = (4/3)*pi*r³.}
Unit Cells - DrBob222, Sunday, May 9, 2010 at 11:30pm
4r = a(2^1/2) and
volume of the atom = (4/3)*pi*r³
Unit Cells - CHeM, Monday, May 10, 2010 at 12:04am
I got it thank you!
The A^3 was suppose to stand for ångström
cubed...
Unit Cells - j, Monday, May 9, 2011 at 1:29am
what does the pi stand for?

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