what is the concentration of lead ions and sulfide ions in a saturated solution of lead sulfide (PbS) solution at 25 degrees celsius.
see below
To determine the concentration of lead ions (Pb2+) and sulfide ions (S2-) in a saturated solution of lead sulfide (PbS), we need to consider the solubility product constant (Ksp) of PbS.
The solubility product constant is an equilibrium constant that relates to the concentration of the dissolved ions in a saturated solution. For PbS, the Ksp expression is:
Ksp = [Pb2+][S2-]
Given that the solution is saturated, the concentrations of lead ions and sulfide ions will be equal. Let's denote the concentration of both ions as "x".
Therefore, the Ksp expression becomes:
Ksp = x * x = x^2
We need the value of the solubility product constant (Ksp) for PbS to compute the concentration. According to the literature, the Ksp for PbS at 25 degrees Celsius is approximately 1.6 x 10^-28.
Using this value, we can set up the equation:
1.6 x 10^-28 = x^2
Solving for "x" using a calculator or any mathematical software, we find that x is approximately 1.3 x 10^-14 M.
Therefore, the concentration of lead ions (Pb2+) and sulfide ions (S2-) in a saturated solution of PbS at 25 degrees Celsius is approximately 1.3 x 10^-14 M.