Posted by Chem on Sunday, May 9, 2010 at 3:42pm.
Have you tried setting up an ICE chart? That's the obvious way to go.
yes I did, but im still not getting the right answer.
I got .1136 which is not the correct answer.
what do you have for
2NO <-> N2 O2
initial .116 0 0
change -x +x +x
equil .116-x x x
Did you look at your post from last night where we arrived at K = something x 10^-192? That problem didn't ask for K, it asked for pK. I'll get back on the current problem.
NO = 0.1160
N2 = 0
O2 = 0
NO = -2x
N2 = x
O2 = x
NO = 0.1160 - 2x
N2 = x
O2 = x
and solve for x.
yes, I figured that one out. Thanks so much for the help!
that works! thank you so much!!
I'm curious about the problem last night. Was the pK about 192?
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