The specific heat capacity (cp) of lead is 0.13 J/g °C. How much heat (in J) is required to raise the temperature of 15 grams of lead from 22 °C to 37 °C?

a. 2.0
b. -0.13
c. 0.13
d. 29

To calculate the amount of heat required to raise the temperature of a substance, you can use the formula:

Q = m * cp * ΔT

Where:
Q = Heat (in joules)
m = Mass of the substance (in grams)
cp = Specific heat capacity of the substance (in J/g °C)
ΔT = Change in temperature (in °C)

In this case, you want to find the amount of heat (Q) required to raise the temperature of 15 grams of lead from 22 °C to 37 °C. Let's plug in the values into the formula:

Q = 15 g * 0.13 J/g °C * (37 °C - 22 °C)

Q = 15 g * 0.13 J/g °C * 15 °C

Q = 29.25 J

Therefore, the amount of heat required to raise the temperature of 15 grams of lead from 22 °C to 37 °C is 29.25 joules.

The correct answer is (d) 29.

see below.