The specific heat capacity (cp) of lead is 0.13 J/g °C. How much heat (in J) is required to raise the temperature of 15 grams of lead from 22 °C to 37 °C?

a. 2.0
b. -0.13
c. 0.13
d. 29

d.29

q = mass x specific heat x delta T.

Well, well, well...it looks like we've got ourselves a heat equation to solve! Let's hop right into it, shall we?

The formula we need here is Q = m * cp * ΔT, where Q is the heat, m is the mass, cp is the specific heat capacity, and ΔT is the change in temperature.

Alright, so let's plug in the numbers: m = 15 g, cp = 0.13 J/g °C, and ΔT = 37 °C - 22 °C = 15 °C.

Now we just need to do some simple multiplication: Q = 15 g * 0.13 J/g °C * 15 °C = 29.25 J.

So, the correct answer is option d, 29 J. Keep spreading the heat knowledge, my friend!

To calculate the amount of heat required to raise the temperature of a substance, we can use the formula:

Q = m * cp * ΔT

where Q is the heat energy, m is the mass, cp is the specific heat capacity, and ΔT is the change in temperature.

In this case, the mass of lead is 15 grams, the specific heat capacity is 0.13 J/g °C, and the change in temperature is 37 °C - 22 °C = 15 °C.

Plugging in these values into the formula:

Q = 15 g * 0.13 J/g °C * 15 °C

Q = 29.25 J

Therefore, the amount of heat required to raise the temperature of 15 grams of lead from 22 °C to 37 °C is 29.25 J.

The answer is (d) 29.

To calculate the amount of heat required to raise the temperature of a substance, you can use the formula:

Q = m * cp * ΔT

Where:
Q = amount of heat energy (in J)
m = mass of the substance (in grams)
cp = specific heat capacity of the substance (in J/g °C)
ΔT = change in temperature (in °C)

In this case, we have:
m = 15 grams
cp = 0.13 J/g °C
ΔT = 37 °C - 22 °C = 15 °C

Plugging in the values into the formula, we get:
Q = 15 grams * 0.13 J/g °C * 15 °C = 29 J

So, the amount of heat required to raise the temperature of 15 grams of lead from 22 °C to 37 °C is 29 J.

Therefore, the correct answer is d. 29.