Posted by Randy on Saturday, May 8, 2010 at 11:23pm.
The x in front of the f is any constant you would put in the equation.
Example: x->5 5=c
lim [xf(x) + 3 g(x)]^2
x->5
so, [5*6 + 5*(-4)]^2
You should be able to do the rest.
[c*6 + 3*(-4)]^2 = (6c -12)^2
= 36c^2 - 144c + 144
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