Posted by Stacey on Friday, May 7, 2010 at 10:12pm.
A ladder 10m long and weighing 50 N rests against a smooth vertical wall. If the ladder is just on the verge of slipping when it makes a 50 degree angle with the ground, find the coefficient of static friction between the ladder and the ground.

Physics  drwls, Saturday, May 8, 2010 at 12:23am
The upper wall exerts only a normal force on the ladder  no friction force. The normal force there (F1) is such that
F1*L sin 50 = W*L/2* cos 50
F1 = (1/2)*W tan 50 = 0.596 W
The normal force at the base equals the weight W, since the other contact point is smooth and frictionless. If it is just about to slip, the maximum static friction force at the base (Ff,max) equals the normal force at the top, which I called F1.
Ff,max = mus*W = F1 = W/2 tan 50
mus = F1/W = (1/2) tan 50 = 0.596
is the static friction coefficient
Answer This Question
Related Questions
 Physics  A ladder 10m long and weighing 50 N rests against a smooth vertical ...
 Physics  A uniform ladder 10.0m long and weighing 50.0N rests against a smooth ...
 statics/physics  The uniform 10kg ladder in the figure rests against the ...
 ap physics b  A uniform ladder 8.09 m long and weighing 201.0 N rests against a...
 physics  An 9.0 m, 210 N uniform ladder rests against a smooth wall. The ...
 phsics  uniform ladder 25 ft long rests against a smooth vertical wall. The ...
 Physics  A uniform ladder of length (L) and weight 100 N rests against a smooth...
 Physics  A 7.68 m, 132 kg uniform ladder rests against a smooth wall. The ...
 physics  A painter climbs a ladder leaning against a smooth wall. At a certain ...
 Physics PLEASE HELP  A painter climbs a ladder leaning against a smooth wall. ...
More Related Questions