Friday

April 18, 2014

April 18, 2014

Posted by **Anonymous** on Friday, May 7, 2010 at 8:05pm.

with some 15%-saline solution to obtain 100 mL of a 12%-saline solution. How much of the 10%-saline solution did the pharmacist use in the mixture?

A 60 mL

B 45 mL

C 40 mL

D 25 mL CAN SOME GIVE AN EQUATION TO HELP MY SOLVE THIS PROBLEM THIS IS THE ONLY WAY TO SOLVE THis problem

- MATH -
**Damon**, Friday, May 7, 2010 at 8:11pmx ml of 10% --->0.1 x salt

(100-x ml) of 15% ----> 0.15(100-x) salt

total salt = .1x + 15 - .15x = 15-.05x salt

so

15-.05x = .12(100) = 12

3 = .05x

x = 60 ml

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