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December 21, 2014

December 21, 2014

Posted by **Anonymous** on Friday, May 7, 2010 at 7:47pm.

P(x) = x^4 - 5x^3 + 7x^2 - 5x + 6; -i

- Algebra 2 -
**bobpursley**, Friday, May 7, 2010 at 8:03pmwell, if one root is -i, it has another root +i, as complex roots will appear in conjugates. (x+i)(x-i)=(x^2+1) is a factor. So, divide that into the polynomial....

(x^4-5x^3+7x^2-5x+6)/(x^2+1)=

x^2-5x+6=(x-3)(x-2)

so the roots are i, -i, 3,2

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