Question

If the voltage of the cell is 0.3579 V at 25.0°C when [Zn2+] = 0.1603 M and the pressure of H2 = 1.000 atm, what is the pH?

Zn(s) + 2 H+(aq) « Zn2+(aq) + H2(g) E° = 0.7630 V

?

Answer 1

My computer doesn't read some of the symbols on your post. Here is what you do.

It appears the problem gives you E^o_cell. Then use
E_cell = E^o_cell - (0.0592/n)*log Q. The Q term will be the location of the (H^+), solve for that and convert to pH.