Posted by **BWB** on Friday, May 7, 2010 at 12:35am.

How many games are played in a women’s soccer conference

if there are eight teams and all teams play each other twice?

(8*7)*2= 56*2=112 games

- math: Am I right? -
**Reiny**, Friday, May 7, 2010 at 1:01am
no,

number of games in one round = C(8,2) = 28

so for two rounds that would be 56

When you take 8*7 that would include cases such as

teamA vs Team B and Team B vs Team A, but that is the same game and in your first 8*7 or 56 games you have 28 such pairs.

So you must divide by 2.

In other words, you have taken the order into play, but this is not a permutation, but rather a combination.

## Answer This Question

## Related Questions

- math - How many games are played in a women's soccer conference if there are ...
- mathematics - How many games are played in a women's soccer conference if there ...
- Math - How many games are played in a soccer competition if there are 7 teams ...
- math - How many games are played in a soccer competition if there are 7 teams ...
- Math - If each 11 football teams In a college athletic conference played each of...
- SAT Math - At a basketball tournament involving 8 team played 4 games with each ...
- Math - each of 5 basketball teams in a league played N games with each of the 4 ...
- Math - The function of g += t^2-t represents the total number of games played by...
- Math - Hillside has 12 teams. Each team plays each other teams twice. How many ...
- Math - Given the following axioms: Axiom 1: Each game is played by two distinct ...

More Related Questions