Posted by **T** on Thursday, May 6, 2010 at 7:18pm.

A baseball diamond is a square 90 feet on a side. The pitcher's mound is 60.5 feet from home. How far does the pitcher have to run to cover first? (we are using the LAW OF SINES AND COSINES)

- Algebra 2 with trigonometry -
**Reiny**, Thursday, May 6, 2010 at 7:22pm
I see it as a simple Pythagorean problem

x^2 + 60.5^2 = 90^2

....

....

x = 66.6 feet

- Correction - Algebra 2 with trigonometry -
**Reiny**, Thursday, May 6, 2010 at 7:26pm
OOPS, I assumed wrongly that the pitcher was halfway between home and second.

the way you state it results in a a Law of Cosine problem

x^2 = 90^ + 60.5^2 - 2(90)(60.54059.857)cos 45

= 4059.857

x = 63.72 feet

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