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March 28, 2017

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A baseball diamond is a square 90 feet on a side. The pitcher's mound is 60.5 feet from home. How far does the pitcher have to run to cover first? (we are using the LAW OF SINES AND COSINES)

  • Algebra 2 with trigonometry - ,

    I see it as a simple Pythagorean problem

    x^2 + 60.5^2 = 90^2
    ....
    ....
    x = 66.6 feet

  • Correction - Algebra 2 with trigonometry - ,

    OOPS, I assumed wrongly that the pitcher was halfway between home and second.

    the way you state it results in a a Law of Cosine problem

    x^2 = 90^ + 60.5^2 - 2(90)(60.54059.857)cos 45
    = 4059.857
    x = 63.72 feet

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