posted by Annalie on .
Consider the reaction
2Al + 3CuSO4 = Al2(SO4)3 + 3Cu
What is the maximum amount of Cu (63.5
g/mol) that could be produced by reacting
20.0 grams of Al (27.0 g/mol) with excess
1. 70.6 g
2. 57.2 g
3. 129 g
4. 31.4 g
I don't understand how to set it up nor what I do with the excess CuSO4
The excess CuSO4 does not react.
Look at the balanced equation. For each mole of Al, 1.5 mole of CuSO4 react.
moles of AL: 20/27
Moles of CuSO4: 20/27*1.5=1.111 moles react.
Mass of reacting CuSO4: 1.111*63.5 grams.