If the density of a 225g stuffed plush toy is 1.25g/cm^3 and the water volume in a glass is 25 ml, find the new level of water after the toy is pushed under water.

I know that D=m/v
so 1.25=225/v
so 1.25/225=v
so I got .005 which cannot possibly be right.
I am obviously doing something wrong. Please help! Thanks!

What is the volume of the toy?

answer: mass/density=225/1.25 cm^3

so, if no water is absorbed, the new volume is.... 25ml+225/1.25 ml

by the way, this line is wrong:

so 1.25/225=v

it should read
so 1.25/225=1/v

You are correct in using the formula D=m/v to find the volume of the toy. However, there seems to be an error in your calculations.

Let's start from the beginning. The formula for density is D = m/v, where D is the density, m is the mass, and v is the volume.

Given that the mass of the stuffed plush toy is 225g and the density is 1.25g/cm^3, we can rearrange the formula to solve for the volume of the toy:

v = m/D

Substituting the values, we have:

v = 225g / 1.25g/cm^3

To simplify the units, we need to convert grams to cm^3. Since 1g = 1cm^3, the units will cancel out:

v = 225 cm^3 / 1.25

Now, divide 225 by 1.25 to find the volume of the toy:

v = 180 cm^3

After finding the volume of the toy, you can proceed to the next step to determine the change in water level after the toy is pushed under the water.

Given that the water volume in the glass is 25 ml, you need to add the volume of the toy to the initial water volume to find the new level of water:

New water level = Initial water level + Volume of toy

New water level = 25 ml + 180 cm^3 (Note: The units need to be consistent, so we convert cm^3 to ml since 1 cm^3 = 1 ml)

New water level = 25 ml + 180 ml

New water level = 205 ml

Therefore, the new level of water after the toy is pushed under water is 205 ml.

To find the new level of water after the toy is pushed under water, we need to use the principle of buoyancy. The buoyant force exerted on an object submerged in a fluid is equal to the weight of the displaced fluid.

To solve this problem, we need to find the volume of the stuffed plush toy. We can use the formula for density, which is mass divided by volume:

Density (D) = mass (m) / volume (v)

Given:
Density of the toy (D) = 1.25 g/cm³
Mass of the toy (m) = 225 g

Rearranging the formula, we have:
Volume (v) = mass (m) / density (D)

Substituting the given values:
Volume (v) = 225 g / 1.25 g/cm³ = 180 cm³

Now, let's find the volume of water displaced by the toy when it is completely submerged. This volume will be equal to the volume of the toy.

Next, we need to find the change in water level. As the toy is pushed under water, it displaces a certain volume of water, causing the water level to rise.

To find the change in water level, we need to subtract the initial water volume (25 mL) from the volume of water displaced by the toy.

Let's calculate the change in water level:
Change in water level = Volume of water displaced - Initial water volume

Volume of water displaced = Volume of toy = 180 cm³
Initial water volume = 25 mL = 25 cm³

Change in water level = 180 cm³ - 25 cm³ = 155 cm³

Therefore, the new level of water after the toy is pushed under water will cause the water level to rise by 155 cm³.