Posted by **Stuck** on Wednesday, May 5, 2010 at 10:29pm.

"In the expansion of (2-ax)^5 the coefficient of x^2 is 5. Find the value of a".

I know I have to use the binomial theorem to help me, but I don't know how.

- Never Mind! -
**Stuck**, Wednesday, May 5, 2010 at 10:35pm
I got it. :)

- Math - another question -
**Anonymous**, Wednesday, May 5, 2010 at 10:36pm
How did u get it?

- Math - another question -
**Stuck**, Wednesday, May 5, 2010 at 11:01pm
According to the binomial theorem, the term with x^2 would be the third term. I plugged my known values into the "formula" for the third term, and made it equal to 5. Then I solved for a. Sorry, my explanation is kind of vague.

- Math - another question -
**Anonymous**, Wednesday, May 5, 2010 at 11:05pm
Cool, I appreciate you responding to my question.

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