Math  another question
posted by Stuck on .
"In the expansion of (2ax)^5 the coefficient of x^2 is 5. Find the value of a".
I know I have to use the binomial theorem to help me, but I don't know how.

I got it. :)

How did u get it?

According to the binomial theorem, the term with x^2 would be the third term. I plugged my known values into the "formula" for the third term, and made it equal to 5. Then I solved for a. Sorry, my explanation is kind of vague.

Cool, I appreciate you responding to my question.