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July 30, 2014

July 30, 2014

Posted by **Kali** on Tuesday, May 4, 2010 at 11:02pm.

- Pre-Calc -
**Damon**, Wednesday, May 5, 2010 at 4:35amTriangle sides 40 and 25 and included angle = 45 degrees. We want the side opposite the 45 degree angle

c^2 = a^2+b^2 - 2ab cos 45

c^2 = 40^2 + 25^2 - 2*40*25 (sqrt 2/2)

c^2 = 1600+625-1414 =810

c=28.5

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