Posted by **Abbey** on Tuesday, May 4, 2010 at 10:02pm.

Find the vertex, focus and directrix of the parabola.

4x - y^2 - 2y - 33 = 0

y^2+2y+1 = -4x+33+1

(y+1)^2 = -4(x+8.5)

vertex:(-1,-8.5)

focus:(-2,-8.5)

Directrix: x=0

Is this correct?

- Math -
**Damon**, Tuesday, May 4, 2010 at 10:18pm
y^2 + 2 y = 4 x - 33

y^2 + 2 y + 1 = 4 x - 32

(y+1)^2 = 4 (x-8)

(8,-1) is the vertex etc.

opens right, a = 4

vertex to focus = 4 so focus at (12,-1)

vertex to directrix = 4 so directrix at x = 4

## Answer this Question

## Related Questions

- algebra - 6. Find the equation of each parabola described below. a) parabola ...
- Math - Find the vertex, focus, and directrix of the parabola. x^2 - 2x + 8y + 9...
- Vertex, Focus, & Directrix of Parabolas - Find the Vertex, Focus, and Directrix ...
- Pre Cal - write the equations of the parabola, the directrix, and the axis of ...
- maths - Given that the equation of the parabola is 5y^2 + 24x = 0. Find (1)The ...
- Math - Find the vertex, focus, and directrix of the parabola. x^2 - 2x + 8y + 9...
- Algebra - Can someone tell me if I am right? I need to find the equation of a ...
- algebra problem - I need to find the equation of a parabola. I am not sure if ...
- Pre Cal Check - focus: (0,p) vertex: if not given, then it is assumed (0,0) ...
- Algebra II - Write an equation for the parabola with focus (1,3) and vertex (0,3...