Posted by Abbey on Tuesday, May 4, 2010 at 10:02pm.
Find the vertex, focus and directrix of the parabola.
4x  y^2  2y  33 = 0
y^2+2y+1 = 4x+33+1
(y+1)^2 = 4(x+8.5)
vertex:(1,8.5)
focus:(2,8.5)
Directrix: x=0
Is this correct?

Math  Damon, Tuesday, May 4, 2010 at 10:18pm
y^2 + 2 y = 4 x  33
y^2 + 2 y + 1 = 4 x  32
(y+1)^2 = 4 (x8)
(8,1) is the vertex etc.
opens right, a = 4
vertex to focus = 4 so focus at (12,1)
vertex to directrix = 4 so directrix at x = 4