Posted by Anonymous on Tuesday, May 4, 2010 at 9:04pm.
find the primary solutions. 4cos^2x3=0 and tanxtan^2x=0.

trig  Reiny, Tuesday, May 4, 2010 at 9:50pm
4cos^2x3=0
cos^2 x = 3/4
cos x = ± √3/2
If by primary solutions you mean 0≤ x ≤ 360
then x = 30°, 150°, 210°, 330°
in radians: π/6, 5π/6, 7π/6,11π/6
the second one:
tanx(1tanx) = 0
tanx = 0, or tanx = 1
let me know what you got for x
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