Posted by **Anonymous** on Tuesday, May 4, 2010 at 9:04pm.

find the primary solutions. 4cos^2x-3=0 and tanx-tan^2x=0.

- trig -
**Reiny**, Tuesday, May 4, 2010 at 9:50pm
4cos^2x-3=0

cos^2 x = 3/4

cos x = ± √3/2

If by primary solutions you mean 0≤ x ≤ 360

then x = 30°, 150°, 210°, 330°

in radians: π/6, 5π/6, 7π/6,11π/6

the second one:

tanx(1-tanx) = 0

tanx = 0, or tanx = 1

let me know what you got for x

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