NaOH(aq) + HCl(aq)----> H20 + Nacl(aq).. solve for the amoont of energy aborbed by the solution. (50ml of 1.0M HCl is 23deg; 50ml of 1.0M NaOH is at 25deg; mixed solutuion= 31deg
pls tell me the steps to take inorder to solve the question. Thanks in advance.
Since the T of the acid and base are not the same I would do it in two steps.
qHCl = mass water x specific heat x (Tfinal-Tinitial).
qNaOH = mass water x specific heat x (Tfinal-Tinitial).
Then add qHCl + qNaOH = total q.
To solve for the amount of energy absorbed by the solution, you can use the equation:
q = mcΔT
where:
q is the energy absorbed (in joules),
m is the mass of the solution (in grams),
c is the specific heat capacity of the solution (in J/g·°C), and
ΔT is the change in temperature (in °C).
Here are the steps to solve the question:
1. Calculate the mass of the solution:
- The solution is a mixture of HCl and NaOH.
- Since both solutions have the same concentration (1.0M) and volume (50ml), the mass of the solution can be calculated using the density relationship: density = mass/volume.
- You will need to convert the volume to mass by multiplying it by the density of the solution.
2. Calculate the change in temperature (ΔT):
- ΔT can be calculated by subtracting the initial temperature of the solution (23°C) from the final temperature of the mixture (31°C).
3. Determine the specific heat capacity (c):
- The specific heat capacity varies with different solutions.
- You can look up the specific heat capacity of the solution in a reference table or assume an average value.
4. Plug the values into the equation q = mcΔT:
- Substitute the mass of the solution, specific heat capacity, and change in temperature into the equation.
- Calculate the energy absorbed (q) in joules.
By following these steps, you should be able to determine the amount of energy absorbed by the solution.