posted by Ade on .
NaOH(aq) + HCl(aq)----> H20 + Nacl(aq).. solve for the amoont of energy aborbed by the solution. (50ml of 1.0M HCl is 23deg; 50ml of 1.0M NaOH is at 25deg; mixed solutuion= 31deg
pls tell me the steps to take inorder to solve the question. Thanks in advance.
Since the T of the acid and base are not the same I would do it in two steps.
qHCl = mass water x specific heat x (Tfinal-Tinitial).
qNaOH = mass water x specific heat x (Tfinal-Tinitial).
Then add qHCl + qNaOH = total q.