Math 9th grade
posted by Nat on .
x^2 + 5x +6/
x^2  3x 10
How do I do this? Is it asking me to divide?
The answer choices are as following:
A)x + 3/
x  5
, x ≠ 5
B)x + 3/
x  5
, x ≠ 2, 5
C)x2 + 5x + 6/
x  5
, x ≠ 5
D)x2 + 5x + 6/
x  5
, x ≠ 2, 5

factor it
( x^2 + 5x +6)/( x^2  3x 10)
= (x+2)(x+3)/[(x5)(x+2)]
= (x+3)/(x5) , x ≠ 2,5
suppose you had (2)(3)/[(3)(7)]
could you not cancel the equal factors to get 2/7
the above question follows the same concept, I canceled the factors (x+2). 
x^2 + 5x +6/
x^2  3x 10
factor top and bottom
(x+2)(x+3) / [(x5)(x+2]
= (x+3) / (x5)
if x = 5 denominator is zero so exclude that point from the domain of x so I say A