Posted by **Nat** on Tuesday, May 4, 2010 at 8:02pm.

x^2 + 5x +6/

x^2 - 3x -10

How do I do this? Is it asking me to divide?

The answer choices are as following:

A)x + 3/

x - 5

, x ≠ 5

B)x + 3/

x - 5

, x ≠ -2, 5

C)x2 + 5x + 6/

x - 5

, x ≠ 5

D)x2 + 5x + 6/

x - 5

, x ≠ -2, 5

- Math 9th grade -
**Reiny**, Tuesday, May 4, 2010 at 8:21pm
factor it

( x^2 + 5x +6)/( x^2 - 3x -10)

= (x+2)(x+3)/[(x-5)(x+2)]

= (x+3)/(x-5) , x ≠ -2,5

suppose you had (2)(3)/[(3)(7)]

could you not cancel the equal factors to get 2/7

the above question follows the same concept, I canceled the factors (x+2).

- Math 9th grade -
**Damon**, Tuesday, May 4, 2010 at 8:23pm
x^2 + 5x +6/

x^2 - 3x -10

factor top and bottom

(x+2)(x+3) / [(x-5)(x+2]

= (x+3) / (x-5)

if x = 5 denominator is zero so exclude that point from the domain of x so I say A

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