Thursday
March 30, 2017

Post a New Question

Posted by on .

x^2 + 5x +6/
x^2 - 3x -10

How do I do this? Is it asking me to divide?
The answer choices are as following:

A)x + 3/
x - 5

, x ≠ 5


B)x + 3/
x - 5

, x ≠ -2, 5


C)x2 + 5x + 6/
x - 5

, x ≠ 5


D)x2 + 5x + 6/
x - 5

, x ≠ -2, 5

  • Math 9th grade - ,

    factor it
    ( x^2 + 5x +6)/( x^2 - 3x -10)
    = (x+2)(x+3)/[(x-5)(x+2)]
    = (x+3)/(x-5) , x ≠ -2,5


    suppose you had (2)(3)/[(3)(7)]
    could you not cancel the equal factors to get 2/7
    the above question follows the same concept, I canceled the factors (x+2).

  • Math 9th grade - ,

    x^2 + 5x +6/
    x^2 - 3x -10

    factor top and bottom
    (x+2)(x+3) / [(x-5)(x+2]

    = (x+3) / (x-5)
    if x = 5 denominator is zero so exclude that point from the domain of x so I say A

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question