Posted by **Abbey(Please help)** on Tuesday, May 4, 2010 at 4:37pm.

Logs are stacked up in apile as shown in the figure. The top row has 15 logs and the bottom row has 21 logs. How many logs are in the stack?

a1= 1+14=15

an= 7+14=21

s1=(n/2)(a1+an)

(n/2)(15+21) = 18

How do I figure out the n?

- Math -
**Abbey(Please help)**, Tuesday, May 4, 2010 at 4:39pm
Would n be 14?

- Math -
**Reiny**, Tuesday, May 4, 2010 at 4:45pm
n/2(26) = 18

26n = 36

n = 36/26

something very wrong with your equation, since n has to a whole number

where does the 18 come from?

you seem to be using the formula

S(n) = n/2(first + last)

so 18 would be the sum of the logs ????

that makes no sense, since the bottom row alone contains 21 logs.

- Math -
**Anonymous**, Wednesday, March 23, 2016 at 11:17pm
No

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