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December 20, 2014

December 20, 2014

Posted by **Abbey(Please help)** on Tuesday, May 4, 2010 at 4:09pm.

(2+2i)^6

a=2 b=2 n=6

r=sqrt 2^2 + 2^2 = sqrt8

Q=7pi/4

(sqrt8)^6 = 512

512(cos 6/1 x 7pi/4) + i sin 6 x 7pi/4

512 (cos 21pi/2) + i sin (21pi/2)

512(cos pi/2) + i (sin pi/2)

512(2+2i)

1024 + 1024i

Is this correct?

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