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October 20, 2014

October 20, 2014

Posted by **Mary** on Tuesday, May 4, 2010 at 3:36pm.

I did "u-substitution" to make it the integral from 1 to 0 of 4^u but then i don 't know where to go from there! Thank you

- Calculus II -
**bobpursley**, Tuesday, May 4, 2010 at 4:21pmINT 4^u du

what is the integral of a^u du?

Ans: a^u / lna

check that.

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