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April 20, 2014

April 20, 2014

Posted by **Mike** on Tuesday, May 4, 2010 at 12:18am.

x = e^t - 12

y = e^2t

(a) Eliminate the parameter to find a Cartesian equation of the curve.

- Curves defined by parameteric equations -
**Reiny**, Tuesday, May 4, 2010 at 7:22amfrom x = e^t - 12

e^t = x+12

t = ln(x+12)

form y = e^2t

2t = lny

t = (lny)/2

so (ln y)/2 = ln(x+12)

lny = 2ln(x+12)

lny = ln(x+12)^2

y = (x+12)^2

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