Posted by peter on Monday, May 3, 2010 at 11:16pm.
sinŲ = x/14
cosŲ = (1/4)dx/dŲ
dx/dŲ = 4cosŲ
so when Ų = π/3
dx/dŲ = 4cosπ/3 = 2
somehow my 14 changed to 4,
(need new specks)
so all the 4's are 14's
and last line is
dx/dŲ = 14cos π/3 = 7
just realized that drwls had already answered the question correctly,
http://www.jiskha.com/display.cgi?id=1272944003
Related Questions
calculus - A ladder 14 ft long rests against a vertical wall. Let \theta be the ...
Math - A ladder 20 ft long rests against a vertical wall. Let \theta be the ...
Math - A ladder 20 ft long rests against a vertical wall. Let \theta be the ...
Calculus Ladder Problem - A ladder 20 ft long rests against a vertical wall. Let...
college - A ladder 10 feet long rests against a vertical wall. If the bottom of ...
math - A ladder 10 ft long rests against a vertical wall. let θ be the ...
Math - a ladder 10 ft long rests against&...
calculus - A ladder 10 ft long rests against a vertical wall. let θ be ...
Math - A ladder 10 ft long rests against a vertical wall. If the bottom of the ...
Related Rates - A ladder 10 ft long rests against a vertical wall. If the bottom...
For Further Reading