Posted by Stuck on Monday, May 3, 2010 at 11:06pm.
"The probability of getting heads on a biased coin is 1/3. Sammy tosses the coin 3 times. Find the probability of getting two heads and one tail".
I thought that all you have to do is:
(1/3)(1/3)(2/3)
It makes sense to me, but it's not right...

Math  PsyDAG, Tuesday, May 4, 2010 at 7:58am
Here are the possibilities:
HHT
HTH
THH
Each one has a probability of (1/3)(1/3)(2/3) = 2/27. For eitheror probabilities, add the probabilities of the individual events.

Math  Anonymous, Sunday, October 31, 2010 at 1:02pm
I WOULD PUT IT AS A SIMPLE 1/3
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