Thursday

April 24, 2014

April 24, 2014

Posted by **jj** on Monday, May 3, 2010 at 10:46pm.

- algebra -
**MathMate**, Monday, May 3, 2010 at 11:26pmThis is a problem in which you need to convert the work rate into something addable.

If Bob does his lawn in 3 hours, he does 1/3 in one hour. Similarly Jane can mow 1/5 of the lawn in one hour.

So in one hour, both working together will mow (1/3)+(1/5)=8/15 of the lawn.

The time it takes to mow the complete lawn is therefore 1/(8/15)=15/8=1 7/8 hours.

- algebra -
**jj**, Tuesday, May 4, 2010 at 12:11amThank you so much!

- algebra :) -
**MathMate**, Tuesday, May 4, 2010 at 8:51amYou're welcome!

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