posted by Anonymous on .
If 1.88 g of copper(II) chloride dihydrate is reduced by Mg(s), what is the minimum mass of Mg(s) required for this reduction?
CuMg --> Cu(s) + Mg
molecular weight= 170.482 CuCl2 . 2H2O
1.88/170.482 = 0.01103 mol CuCl2 . 2H2O
=0.01103 mol Mg
0.01103 * 24.31* 100 = 268 mg
is this correct?