Sunday

August 31, 2014

August 31, 2014

Posted by **Stuck** on Monday, May 3, 2010 at 8:45pm.

(Answer: 1/28)

So I thought about doing 4 cases and then adding them up (don't pick red ball in A, don't pick red ball in B...pick red ball in A, pick red ball in B...etc...).

I did this:

(3/8)(3/7)(6/10)(6/9) +

(3/8)(2/7)(6/10)(5/9) +

.....

But it doesn't work. What am I doing wrong?

- Math -
**Reiny**, Monday, May 3, 2010 at 9:46pmSince you pick 2 from each vase, and you want 4 reds, there is only one way, that is, you pick 2 from A and 2 from B.

which is C(3,2)/(C(8,2) * C(6,2)/C(10,2)

= 3/28 * 15/45 = 1/28

- Math -
**Stuck**, Monday, May 3, 2010 at 10:17pmOh yeah! Thank you!

**Related Questions**

Finite Math-Probability - Suppose we have an urn with 10 white balls and 6 red ...

math - A basket contains 15 red numbered balls and 10 white numbered balls. A ...

Strayer University - An urn contains white balls and red balls. If Juan chooses ...

finite math - A box contains 14 balls (10 red and 4 white). Three balls randomly...

Statistic - A urn contains 21 red balls, 14 white balls If we randomly select 2 ...

Math - Four balls are simultaneously picked at random from a jar containing 2 ...

Finite Math - An urn contains six red balls and five white balls. A sample of 2 ...

math - A box contains 6 red balls, 4 white balls, and 5 green balls. If three ...

Math - A box containing 20 yellow balls, 9 red balls and 6 blue balls. If the ...

Statistics - math - An urn contains 5 red balls and 10 white balls. 6 balls are ...