Friday

February 27, 2015

February 27, 2015

Posted by **Dee** on Monday, May 3, 2010 at 7:06pm.

Solve the equation in the interval [0°, 360°).

csc θ = 1 + cot θ

- trig -
**Reiny**, Monday, May 3, 2010 at 10:13pm1/sinθ = 1 + cosθ/sinθ

1 = sinθ + cosθ

1 - sinθ = cosθ

1-2sinθ + sin^2 θ = cos^2 θ

1 - 2sinθ + sin^2 θ = 1 - sin^2 θ

2sin^2 θ - 2sinθ = 0

2sinθ(sinθ - 1) = 0

sinθ = 0, θ = 0,180,360°

or sinθ = 1 , θ = 90°

but,...

since we squared, all our answers must be verified.

since csc x is undefined for x = 0,180, 360 none of those will work

so x = 90°

**Answer this Question**

**Related Questions**

Precalc/Trig - Sorry there are quite a few problems, but I just need to know if ...

Trig - Given that csc θ = -4 and tan θ > 0, find the exact value of...

Trig - Given that tan θ = - (√3/8) and θ is in QII, find the ...

Trig - Use a calculator to find θ to the nearest tenth of a degree, if 0° &...

trig - The terminal side of θ lies on a given line in the specified ...

precalculus - #1 cscθ-cotθ #2 cosθ(tanθ-secθ) #3 tan&#...

Trig - Write the following in terms of sin(θ) and cos(θ); then ...

TRIG - Find the remaining trigonometric ratios of θ if sin(θ) is ...

trig - use basic identities to simplify the expression. csc θ cot θ / ...

math - Solve the following equation for theta (θ) over the given domain: &#...