Posted by Dee on Monday, May 3, 2010 at 7:06pm.
Can someone please help me solve this equation?
Solve the equation in the interval [0°, 360°).
csc θ = 1 + cot θ

trig  Reiny, Monday, May 3, 2010 at 10:13pm
1/sinθ = 1 + cosθ/sinθ
1 = sinθ + cosθ
1  sinθ = cosθ
12sinθ + sin^2 θ = cos^2 θ
1  2sinθ + sin^2 θ = 1  sin^2 θ
2sin^2 θ  2sinθ = 0
2sinθ(sinθ  1) = 0
sinθ = 0, θ = 0,180,360°
or sinθ = 1 , θ = 90°
but,...
since we squared, all our answers must be verified.
since csc x is undefined for x = 0,180, 360 none of those will work
so x = 90°
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