Post a New Question

physics

posted by on .

An elevator in a tall building is allowed to reach a maximum speed of 3.0 m/s going down. What must the tension be in the cable to stop this elevator over a distance of 2.4 m if the elevator has a mass of 1500 kg including occupants? Need step by step help please!

  • physics - ,

    find the accelearation:

    Vf^2=Vi^2+2ad

    a= -1/2 Vi^2/d= in my head....-4.5/2.4

    tension= mass(g+4.5/2.4)

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question