physics
posted by Anonymous on .
An elevator in a tall building is allowed to reach a maximum speed of 3.0 m/s going down. What must the tension be in the cable to stop this elevator over a distance of 2.4 m if the elevator has a mass of 1500 kg including occupants? Need step by step help please!

find the accelearation:
Vf^2=Vi^2+2ad
a= 1/2 Vi^2/d= in my head....4.5/2.4
tension= mass(g+4.5/2.4)