Thursday

December 18, 2014

December 18, 2014

Posted by **Scott** on Monday, May 3, 2010 at 2:35pm.

3/(y+2) / (7/y-4))

= 3/(y+2) * (y-4)/7

= (3y-12)/(7y+14) or

3(y-4)/[7(y+2)]

- Math-Reiny -
**Reiny**, Monday, May 3, 2010 at 3:48pmYou had typed :

3/y+2 over 7/y-4

or as I read it

3/(y+2) / 7/(y-4)

Unless you made a typing error, my answers stands

If your teacher claims the answer is

3 + 2y/7-4y, do you mean (3+2y)/(7-4y)

we can test this with any number, why not y = 0

original value = 3/(0+2) / 7/(0-4)

= (3/2) / (7/-4)

= (3/2)(-4/7) = -12/14 = -6/7

my answer:

3(0-4)/[7(0+2)] = -12/14 = -6/7

your teachers's answer

(3+0)/(7-0) = 3/7

mmmhhh?

check your typing

**Answer this Question**

**Related Questions**

Algebra-Reiny please explain this - Hi Reiny, I posted this problem earlier and ...

Algebra - I already posted this question and Reiny answered it, I just wanted ...

Algebra - I posted this earlier but it didn't get answered. So I'm posting it ...

Math - I posted this problem the other day and someone answered it but when I ...

math - Sorry, Reiny, I copied the 2nd choice incorrectly. I had posted this ...

calculus - hi I posted this question earlier: what is the median waiting time ...

Belinda, Math - I aked the instructor about that problem that looked like this...

math,drbob222 - I'm sorry the problems i posted had a couple of errors how i ...

MATH - PLEASE HELP! - Need help with combining like terms How do I figure this ...

Math - I had posted this problem with you before and the answer given was 2b =A/...