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April 23, 2014

April 23, 2014

Posted by **Scott** on Monday, May 3, 2010 at 2:35pm.

3/(y+2) / (7/y-4))

= 3/(y+2) * (y-4)/7

= (3y-12)/(7y+14) or

3(y-4)/[7(y+2)]

- Math-Reiny -
**Reiny**, Monday, May 3, 2010 at 3:48pmYou had typed :

3/y+2 over 7/y-4

or as I read it

3/(y+2) / 7/(y-4)

Unless you made a typing error, my answers stands

If your teacher claims the answer is

3 + 2y/7-4y, do you mean (3+2y)/(7-4y)

we can test this with any number, why not y = 0

original value = 3/(0+2) / 7/(0-4)

= (3/2) / (7/-4)

= (3/2)(-4/7) = -12/14 = -6/7

my answer:

3(0-4)/[7(0+2)] = -12/14 = -6/7

your teachers's answer

(3+0)/(7-0) = 3/7

mmmhhh?

check your typing

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