Posted by **dani** on Monday, May 3, 2010 at 1:47pm.

Not sure where to go next. I need to solve this quadratic equation 7x^2-5=0.

This is what I have so far, not sure where/what to do next

x=2/7

x=sqrt2/7 or x=-sqrt2/7* =+/-sqrt2/7

+/-sqrt14/7

not even sure if this is right.

## Answer this Question

## Related Questions

- Precalculus - Given: f(x) = X^2-x evaluate: f(sqrt2 + 3) I have worked out this ...
- math - I have to find an exact solutions on the interval [0,pi) for both of ...
- Algebra II (check) - Assume that no denominator equals 0. sqrt12 - sqrt18 + ...
- Algebra 2 - Simplify: (2^(1+sqrt2)/2^(1-sqrt2))^sqrt2 I need all of the steps. I...
- Calculus Help!!!! - Fnd the derivative if y=x^(1+sqrt2) Is this right (1+sqrt2...
- more math - sqrt50/sqrt2 (sqrt50)/(sqrt2)*(sqrt2/sqrt2)= (sqrt50*sqrt2)/2 =...
- algebra - Can someone please check my work on this problem? For some reason, I ...
- pre-calc - Can someone check my work please? Convert each polar equation to a ...
- Math - Is this correct: sqrt2/sqrt10=sqrt2/5sqrt2 nope. it would be sqrt2/(sqrt5...
- Calculus length of curve - Hi--can anybody show me how to do this? Find the ...