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December 18, 2014

December 18, 2014

Posted by **LiNnda** on Monday, May 3, 2010 at 10:54am.

- equations trig -
**Reiny**, Monday, May 3, 2010 at 11:56am2(1 - sin^2x) - 3sinx = 0

-2sin^2x - 3sinx + 2 = 0

2sin^2x + 3sinx - 2 = 0

(2sinx -1)(sinx + 2) = 0

sinx = 1/2 or sinx = -2

x = 30° or 150° or (sinx = -2 has no solution)

x = 30 or 150 ° which is also π/6 or 5π/6 radians

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