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trig

posted by on .

How do you solve for these identities:
1-sin^2è/cosè= cosè

sin^4è-cos^4è=2sin^2è-1

  • trig - ,

    that e symbol is suppose to be theta.

  • trig - ,

    LS
    = 1-sin^2Ø/cosØ
    = cos^2 Ø/cos
    = cos Ø = RS


    Ls
    = sin^4Ø-cos^4Ø
    = (sin^2Ø + cos^2Ø)(sin^2Ø - cos^2Ø)
    = 1( sin^2Ø - (1-sin^2Ø))
    = 2sin^2Ø - 1
    = RS

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