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December 22, 2014

December 22, 2014

Posted by **Anonymous** on Monday, May 3, 2010 at 10:10am.

1-sin^2è/cosè= cosè

sin^4è-cos^4è=2sin^2è-1

- trig -
**Anonymous**, Monday, May 3, 2010 at 10:16amthat e symbol is suppose to be theta.

- trig -
**Reiny**, Monday, May 3, 2010 at 12:11pmLS

= 1-sin^2Ø/cosØ

= cos^2 Ø/cos

= cos Ø = RS

Ls

= sin^4Ø-cos^4Ø

= (sin^2Ø + cos^2Ø)(sin^2Ø - cos^2Ø)

= 1( sin^2Ø - (1-sin^2Ø))

= 2sin^2Ø - 1

= RS

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