algebra IIURGENT
posted by bev on .
the perimeter of a rectangular yard is 270 feet. If its length is 25 feet greater than its width what are the dimensions of the yard

P=2l+2w
270=2(w+25)+2w
270=2w+50+2w
220=4w
55=w
so
l=w+25
=55+25
=80
Check
P=2l+2w
270=2(80)+2(55)
270=160+110
270=270